neraca massa pulp dan kertas

Neraca Massa Pembuatan Kertas

                Pembuatan kertas menggunakan mesin fourdrinier, pada dasarnya hanyalah pengurangan kadar air dan tidak terjadi reaksi.

WIRE

Air

                                     1500 kg (A)                                                                   C = .......Kg

Pulp                                                   

                Pulp  0,5% =........Kg                                                              Pulp  20% = .....kg

                Air    99,5% =......Kg                                                                          Air  80% = .....Kg

                                                                                White Water (B)=......Kg

·         Persamaan Neraca Massa tanpa reaksi

                                Laju masuk = laju keluar + akumulasi

                                           A       =     B +             C

Kandungan Pulp di A ( Input)

                Pulp =    x 1500 Kg = 7,5 Kg

                Air    =   x 1500 Kg  = 1.492,5 Kg

Neraca Massa

·         Air

99,5% A                =             100% B                  +             80% C

0,995 A                 =                 B                         +             0,8 C

 0,995 (1500)Kg  =                 B                         +             0,8 C

1.492,5 Kg            =                 B                         +             0,8 C..................................(1)

·         Pulp

0,5% A                  =             0% B                      +             20% C

0,005% A              =             0% B                      +             0,2 C

0,005 (1500) Kg  =             0,2 C

7,5 kg                    =             0,2 C

C                             =             37,5 Kg                                           .....................................(2)

Masukkan nilai C ke dalam persamaan (1)

                Sehingga didapatkan

                                1.492,5 Kg            =                 B                         +             0,8 C

                                1.492,5 Kg            =                 B                         +             0,8 (37,5) Kg

                                                B             =                             1.462,5 Kg

Kandungan Pulp 20%      =              x 37,5 Kg = 7,5 Kg

Kandungan Air   80%       =              X 37,5 Kg = 30 Kg

Neraca Massa Pulp          =             7,5 Kg

Neraca Massa Air             =             30 Kg + 1.462,5 Kg = 1.492,5 Kg

Neraca Massa Total         =             7,5 Kg + 1.492,5 Kg = 1.500 Kg     

Komponen	Input (Kg)	Output (Kg)
Pulp Air White Water	7,5 1.492,5 -	7,5 30 1.462,5
Total	1.500	1.500

WIRE

Air

                                     1500 kg (A)                                                                   C = 37,5Kg

Pulp                                                   

Pulp 0,5%    = 7,5 Kg                                                                         Pulp  20% = 7,5 Kg

Air    99,5%  = 1.492,5Kg                                                                                 Air     80% = 30 Kg

                                                                                White Water  = 1.462,5 Kg

A = 37,5 Kg                                                                                                           C = ......... Kg

PRESSURE ROLL WIRE

Pulp 20% = 7,5 Kg                                                                                             Pulp 40 % =......Kg

Air    80% = 30 Kg                                                                                               Air  60%    =......Kg

                                                                       White Water (B) = ......Kg

·         Persamaan Neraca Massa tanpa reaksi

                                Laju masuk = laju keluar + akumulasi

                                           A       =     B +             C

Neraca Massa

·         Air

80% A                    =             100% B                  +             60% C

0,8   A                    =                 B                         +             0,6 C

 0,8 (37,5)Kg       =                 B                         +             0,6 C

30 Kg                     =                 B                         +             0,6 C..................................(1)

·         Pulp

20% A                    =             0% B                      +             40% C

0,2% A                  =             0% B                      +             0,4 C

0,2 (37,5) Kg       =             0,4 C

7,5 kg                    =             0,4 C

C                             =             18,75 Kg                               ............................................(2)

Masukkan nilai C ke dalam persamaan (1)

                Sehingga didapatkan

                                30 Kg                     =                 B                         +             0,6 C

                                30 Kg                     =                 B                         +             0,6 (18,75) Kg

                                                B             =                 11,25 Kg

Kandungan Pulp 40%      =              x 18,75 Kg = 7,5 Kg

Kandungan Air   60%       =              X 18,75 Kg = 11,25 Kg

Neraca Massa Pulp          =             7,5 Kg

Neraca Massa Air             =             11,25 Kg + 18,75 Kg = 30 Kg

Neraca Massa Total         =             7,5 Kg + 30 Kg   = 37,5 Kg               

Komponen	Input (Kg)	Output (Kg)
Pulp Air White Water	7,5 30 -	7,5 11,25 18,75
Total	37,5 Kg	37,5 Kg

A = 37,5 Kg                                                                                                           C = 18,75 Kg

PRESSURE ROLL WIRE

Pulp 20% = 7,5 Kg                                                                                             Pulp 40 % = 7,5Kg

Air    80% = 30 Kg                                                                                               Air  60%    =11,25 Kg

                                                           White Water (B) =18,75 Kg

A = 18,75 Kg                                                                                                         C = ......... Kg

SUCTION ROLL WIRE

Pulp 40% = 7,5 Kg                                                                                             PulP 60 % =......Kg

Air    60% = 11,25 Kg                                                                                         Air  40%    =......Kg

                                                                       White Water (B) = ......Kg

·         Persamaan Neraca Massa tanpa reaksi

                                Laju masuk = laju keluar + akumulasi

                                           A       =     B +             C

Neraca Massa

·         Air

60% A                    =             100% B                  +             40% C

0,6   A                    =                 B                         +             0,4 C

 0,6 (18,75)Kg     =                 B                         +             0,4 C

11,25 Kg               =                 B                         +             0,4C..................................(1)

·         Pulp

40% A                    =             0% B                      +             60% C

0,4 A                      =             0% B                      +             0,6 C

0,4 (18,75) Kg     =             0,6 C

 7,5 kg                   =             0,6 C

C                             =             12,5 Kg                             ............................................(2)

Masukkan nilai C ke dalam persamaan (1)

                Sehingga didapatkan

                                11,25 Kg                               =                 B                         +             0,4 C

                                11,25 Kg                               =                 B                         +             0,4 (12,5) Kg

                                                B                             =                 11,25 Kg           -              5 Kg

                                                B                             =                 6,25 Kg

Kandungan Pulp 60%      =              x 12,5 Kg = 7,5 Kg

Kandungan Air   40%       =              X 12,5 Kg = 5 Kg

Neraca Massa Pulp          =             7,5 Kg

Neraca Massa Air             =             5 Kg + 6,25 Kg                     =  11,25 Kg

Neraca Massa Total         =             7,5 Kg + 11,25 Kg               =  18,75   Kg        

Komponen	Input (Kg)	Output (Kg)
Pulp Air White Water	7,5 11,25 -	7,5 5 6,25
Total	18,75 Kg	18,75 Kg

A = 18,75 Kg                                                                                                         C = 12,5  Kg

SUCTION ROLL WIRE

Pulp 40% = 7,5 Kg                                                                                             PulP 60 % = 7,5 Kg

Air    60% = 11,25 Kg                                                                                         Air  40%    = 5 Kg

                                                                       White Water (B) = 6,25 Kg

A = 12,5 Kg                                                                                                           C = ......... Kg

DRYER WIRE

Pulp 60% = 7,5 Kg                                                                                             PulP 99,5 % =......Kg

Air    40% = 11,25 Kg                                                                                         Air  0,5%    =......Kg

                                                                       White Water (B) = ......Kg

·         Persamaan Neraca Massa tanpa reaksi

                                Laju masuk = laju keluar + akumulasi

                                           A       =     B +             C

Neraca Massa

·         Air

40% A                    =             100% B                  +             0,5% C

0,4   A                    =                 B                         +             0,005 C

 0,4 (12,5)Kg       =                 B                         +             0005 C

5 Kg                        =                 B                         +             0,005C..................................(1)

·         Pulp

0,6% A                  =             0% B                      +             99,5% C

0,6 A                      =             0% B                      +             0,995 C

0,6 (12,5) Kg       =             0,995 C

 7,5 kg                   =             0,995 C

C                             =             7,537 Kg                                          ............................................(2)

Masukkan nilai C ke dalam persamaan (1)

                Sehingga didapatkan

                                5 Kg                                        =                 B                         +             0,005 C

                                5 Kg                                        =                 B                         +             0,005 (7,537) Kg

                                                B                             =                 5 Kg                    -              0,037685 Kg

                                                B                             =                4,962315 Kg

Kandungan Pulp 99,5% =              x 7,537 Kg = 7,499315 Kg

Kandungan Air   0,5%      =              X 7,537 Kg = 0,037685 Kg

Neraca Massa Pulp          =             7, 499315 Kg

Neraca Massa Air             =             0,037685  Kg + 4,962315  Kg          =  5 Kg

Neraca Massa Total         =             7, 499315 Kg + 5Kg           = 12, 499315 Kg

Komponen	Input (Kg)	Output (Kg)
Pulp Air White Water	7,5 5   -	7, 499315 0,037685    4,962315
Total	12,5 Kg	12,499315 Kg

A = 12,5 Kg                                                                                                           C = 12,5  Kg

DRYER WIRE

Pulp 60% = 7,5 Kg                                                                                             Pulp 99,5 % = 7,499315 Kg

Air    40% = 5 Kg                                                                                                 Air  0,5%    = 0,037685   Kg

                                                                       White Water (B) = 4,962315  Kg

FINISHED PAPER

                Pada proses ini hanya terjadi penghalusan permukaan pulp / finished paper dan penggulungan kertas dalam ukuran besar (calendering roll).

                White water Total            = 1.462,5 Kg + 18,75 Kg + 6,25 Kg + 4,962315 Kg = 1.492,462315 Kg

                Pulp (produk)                    = 7,499315 Kg

Air ( H₂O Produk)             = 0,037685 Kg

Neraca Massa Total (dari keseluruhan proses )   = 1.499,962315 Kg

Tabel neraca massa dari keseluruhan proses

Komponen	Input (Kg)	Output (Kg)
Pulp Air White Water	7,5 1.492,5 -	7,499315 0,037685 1.492,462315
Total	1.500 Kg	1.499,962315 Kg